這是宣告一條ScanLine的用法，如果我現在要宣告50條來對Image1做處理的話，要怎麼寫??謝謝 byte *ptr1=NULL; ptr1 = (Byte *)Image1->Picture->Bitmap->ScanLine[i];

哈囉,penny015    你可以宣告一個大小為50的矩陣來儲存,試試看吧。 < class="code"> Byte *ptr[50]; for (int y = 0; y < 50; y＋＋) ptr[y] = (Byte *)pBitmap->ScanLine[y]; /* The first step toward proving things for yourself is to understand how others have done it before! */

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The first step toward proving things for yourself is to understand how others have done it before!

這樣做有意義嗎？ 為什麼要搞50條？

penny015 您好：    fusung 大大應該算回答了您的問題了！ 您是不是希望像存取二維陣列那樣來處理影像呢？ 底下有我之前寫過以二維方式處理彩色轉灰階的程式碼，您參考看看！ < class="code"> void to2D(TImage *image) { Byte **ptr; int r, g, b, gray, index; image->Picture->Bitmap->PixelFormat = pf24bit; ptr = new Byte*[image->Picture->Height]; for (int k=0; kPicture->Height; k ) ptr[k] = (Byte*) image->Picture->Bitmap->ScanLine[k]; for (int row=0; rowPicture->Height; row ) { index = 0; for (int col=0; colPicture->Width; col ) { b = ptr[row][index ]; g = ptr[row][index 1]; r = ptr[row][index 2]; gray = 0.299*r 0.587*g 0.114*b; ptr[row][index ] = (Byte)gray; ptr[row][index 1] = (Byte)gray; ptr[row][index 2] = (Byte)gray; index = 3; } } delete [] ptr; } 原始連結：http://delphi.ktop.com.tw/topic.php?TOPIC_ID=66958 RichTop 敬上 =====***** 把數學當工具，可以解決問題；將數學變能力，能夠發現並解決問題！ =====#####