將256色(8Bit)的圖做浮水印嵌入一張24Bit的圖 我是使用取代24Bit的RGB三色的LSB 如: R(8Bit) G(8Bit) B(8Bit) 8Bit的圖分3Bit嵌入R,分3Bit嵌入G,分3Bit嵌入B 到這裡都沒問題,問題是在取出的時候,有正確的取出那8Bit的數值,但那個數值應該是要256色才對,不過卻把它當作24Bit方式 如:取出156 取出的浮水印RGB(156,0,0) 可以請問高手如何設定呢? 我的取出程式碼 int j, k, x, MoveBit; TColor ProcessColor; byte SourceRGB, TotalWaterMark; Graphics::TBitmap *BitImage=new Graphics::TBitmap; BitImage->Height=ImageProcess->Height; BitImage->Width=ImageProcess->Width; BitImage->PixelFormat=pf8bit; BitImage->Canvas->FillRect(Rect(0,0,BitImage->Width,BitImage->Height)); for (j=0; j<=ImageProcess->Width; j ) { for (k=0; k<=ImageProcess->Height; k ) { ProcessColor=ImageProcess->Canvas->Pixels[j][k]; TotalWaterMark=0; //--------------------------------------------------------------------------- SourceRGB=GetRValue(ProcessColor); for (MoveBit=0; MoveBit<=2; MoveBit ) { x=(SourceRGB>>MoveBit) & 1; TotalWaterMark =x*pow(2,MoveBit); } //--------------------------------------------------------------------------- SourceRGB=GetGValue(ProcessColor); for (MoveBit=0; MoveBit<=2; MoveBit ) { x=(SourceRGB>>MoveBit) & 1; MoveBit =3; TotalWaterMark =x*pow(2,MoveBit); MoveBit-=3; } //--------------------------------------------------------------------------- SourceRGB=GetBValue(ProcessColor); for (MoveBit=0; MoveBit<=1; MoveBit ) { x=(SourceRGB>>MoveBit) & 1; MoveBit =6; TotalWaterMark =x*pow(2,MoveBit); MoveBit-=6; } //--------------------------------------------------------------------------- BitImage->Canvas->Pixels[j][k]=TotalWaterMark; } } ImageWaterMark->Picture->Bitmap->Assign(BitImage); ImageWaterMark->Height=ImageProcess->Picture->Height; ImageWaterMark->Width=ImageProcess->Picture->Width;

您好:    PO程式碼的方式與版規說明請參考下面連結,煩請修改謝謝您的配合 >