如題 請問如何偵測螢幕的解析度? 例如 當1024 * 768 變成 800 * 600時候 如何得知已經變成 800 * 600了

AJCooer: DEVMODE deDisplayMode; EnumDisplaySettings( NULL, ENUM_CURRENT_SETTINGS, &deDisplayMode); //deDisplayMode.dmPelsWidth 寬度 //deDisplayMode.dmPelsHeight 高度

提供另一個取得方法：    範例來自bcb的help         

The following code determines the height of all forms on the screen and resizes any that are taller than the screen height.    for (int i = 0; i < Screen->FormCount; i  )    {
  if (Screen->Forms[i]->Height > Screen->Height)
    Forms[i]->Height = Screen->Height;
  if (Screen->Forms[i]->Width > Screen->Width)
    Forms[i]->Width = Screen->Width;
}
 

int iScrWidth,iScrHeight; iScrWidth = GetSystemMetrics(SM_CXSCREEN); iScrHeight = Screen->Height;

嗯  各位大大     小弟大概了解了< > 謝謝 各位大大的幫忙.大家的說法都對我有幫助 真是難以抉擇要如何給分ㄟ< > 嗯 待我想想